graciozzo: difference between revisions

From Wiktionary, the free dictionary
Jump to navigation Jump to search
Content deleted Content added
Created page with "==Ladino== ===Adjective=== {{lad-adj|g=m}} # {{lb|lad|Haketia}} {{altform|grasiozo|lang=lad}}. es:graciozzo"
 
Line 2: Line 2:


===Adjective===
===Adjective===
{{lad-adj|g=m}}
{{lad-adj|g=m|l}}


# {{lb|lad|Haketia}} {{altform|grasiozo|lang=lad}}.
# {{lb|lad|Haketia}} {{altform|grasiozo|lang=lad}}.

Revision as of 19:10, 8 June 2016

Ladino

Adjective

Lua error in Module:lad-headword at line 49: Parameter 1 is not used by this template.

  1. (Haketia) (deprecated use of |lang= parameter) Alternative form of grasiozo.