ḱr̥h₂os-

Fragment of a discussion from User talk:Rua
Jump to navigation Jump to search

I guess so? But the question, perhaps, is whether this is a new root or merely an existing root with some kind of suffix.

CodeCat13:56, 11 September 2015

Nussbaum has a whole book dedicated to this root. I haven't read it. Let's keep everything on one page until someone sorts things out.

Vahag (talk)14:01, 11 September 2015